If A = {4(n – 1); n ∈ N} and B = {4n – 4n : n ∈ N} where N is the set of natural numbers, then which one is true?

The question seems to be incomplete as there is no list of statements provided to determine which one is true. However, I can help you understand the sets A and B.

Set A = {4(n – 1); n ∈ N} means that we take each natural number n, subtract 1, multiply by 4, and that's our set. So for n = 1, 2, 3, ..., we get A = {0, 4, 8, 12, ...}.

Set B = {4n – 4n : n ∈ N} is a bit tricky because it seems like there might be a typo. As it stands, for any natural number n, 4n – 4n would always be 0, so B would be a set of only 0s. If it's a typo and it should be 4n - 4, then for n = 1, 2, 3, ..., we get B = {0, 4, 8, 12, ...}.

If the sets are as I've interpreted them, then A and B are equal. But without a list of statements to choose from, I can't definitively answer your question.