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You are given an integer array nums sorted in non-decreasing order.Build and return an integer array result with the same length as nums such that result[i] is equal to the summation of absolute differences between nums[i] and all the other elements in the array.In other words, result[i] is equal to sum(|nums[i]-nums[j]|) where 0 <= j < nums.length and j != i (0-indexed).

Question

You are given an integer array nums sorted in non-decreasing order.Build and return an integer array result with the same length as nums such that result[i] is equal to the summation of absolute differences between nums[i] and all the other elements in the array.In other words, result[i] is equal to sum(|nums[i]-nums[j]|) where 0 <= j < nums.length and j != i (0-indexed).

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Solution

Sure, here is a Python solution for the problem:

def sum_of_absolute_differences(nums):
    n = len(nums)
    result = [0] * n
    total_sum = sum(nums)
    prefix_sum = 0

    for i in range(n):
        result[i] = (i * nums[i] - prefix_sum) + (total_sum - prefix_sum - (n - i) * nums[i])
        prefix_sum += nums[i]

    return result

Here is a step-by-step explanation of the solution:

  1. Initialize the length of the array n and the result array result with the same length as nums, filled with zeros.

  2. Calculate the total sum of the array nums.

  3. Initialize a variable prefix_sum to keep track of the sum of the elements before the current index.

  4. Iterate over the array nums. For each index i, calculate the sum of absolute differences between nums[i] and all the other elements in the array. This is done by subtracting the prefix sum from i * nums[i] (which gives the sum of absolute differences for all elements before i) and adding the sum of absolute differences for all elements after i, which is calculated as total_sum - prefix_sum - (n - i) * nums[i].

  5. Add nums[i] to the prefix sum.

  6. Return the result array.

This problem has been solved

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