In wolves, the allele for brown eyes (B) is dominant to the allele for blue eyes (b). The allele for grey coat (G) is dominant to the allele for black coat (g). What are the phenotypic fractions when you cross a wolf that is heterozygous for both brown eyes and grey coat with a wolf that has heterozygous brown eyes and a black coat? Question 18 options: 3/8 brown eyes, grey coat (wolves) 3/8 brown eyes, black coat (wolves) ½ blue eyes, grey coat (wolves) 2/3 brown eyes, grey coat (wolves) ½ blue eyes, grey coat (wolves) 3/8 brown eyes, grey coat (wolves) 3/8 brown eyes, black coat (wolves) 1/8 blue eyes, grey coat (wolves) 1/8 blue eyes, black coat (wolves) 2/3 brown eyes, black coat (wolves) ½ blue eyes, grey coat (wolves) 2/3 brown eyes, grey coat (wolves) ½ blue eyes, black coat (wolves)
Question
In wolves, the allele for brown eyes (B) is dominant to the allele for blue eyes (b). The allele for grey coat (G) is dominant to the allele for black coat (g).
What are the phenotypic fractions when you cross a wolf that is heterozygous for both brown eyes and grey coat with a wolf that has heterozygous brown eyes and a black coat?
Question 18 options:
3/8 brown eyes, grey coat (wolves)
3/8 brown eyes, black coat (wolves)
½ blue eyes, grey coat (wolves)
2/3 brown eyes, grey coat (wolves)
½ blue eyes, grey coat (wolves)
3/8 brown eyes, grey coat (wolves)
3/8 brown eyes, black coat (wolves)
1/8 blue eyes, grey coat (wolves)
1/8 blue eyes, black coat (wolves)
2/3 brown eyes, black coat (wolves)
½ blue eyes, grey coat (wolves)
2/3 brown eyes, grey coat (wolves)
½ blue eyes, black coat (wolves)
Solution
To solve this problem, we need to use a Punnett square to determine the possible genotypes and phenotypes of the offspring.
Step 1: Identify the genotypes of the parents.
The first wolf is heterozygous for both brown eyes and grey coat, so its genotype is BbGg. The second wolf is heterozygous for brown eyes and has a black coat, so its genotype is Bbgg.
Step 2: Set up a Punnett square for each trait.
For the eye color trait, the Punnett square would look like this:
| B | b | |
|---|---|---|
| B | BB | Bb |
| b | Bb | bb |
This gives us 1 BB, 2 Bb, and 1 bb.
For the coat color trait, the Punnett square would look like this:
| G | g | |
|---|---|---|
| g | Gg | gg |
| g | Gg | gg |
This gives us 2 Gg and 2 gg.
Step 3: Determine the phenotypic ratios.
For eye color, 3 out of 4 (or 3/4) will have brown eyes (BB or Bb) and 1 out of 4 (or 1/4) will have blue eyes (bb).
For coat color, 1 out of 2 (or 1/2) will have a grey coat (Gg) and 1 out of 2 (or 1/2) will have a black coat (gg).
Step 4: Combine the ratios.
To get the combined phenotypic ratios, we multiply the ratios for each trait:
- Brown eyes, grey coat: 3/4 * 1/2 = 3/8
- Brown eyes, black coat: 3/4 * 1/2 = 3/8
- Blue eyes, grey coat: 1/4 * 1/2 = 1/8
- Blue eyes, black coat: 1/4 * 1/2 = 1/8
So, the correct answer is:
3/8 brown eyes, grey coat (wolves) 3/8 brown eyes, black coat (wolves) 1/8 blue eyes, grey coat (wolves) 1/8 blue eyes, black coat (wolves)
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