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What is the output of the following code snippet?class MyClass {    static int count = 0;    public MyClass() {        count++;    }    public static int getCount() {        return count;    }}public class Main {    public static void main(String[] args) {        MyClass obj1 = new MyClass();        MyClass obj2 = new MyClass();        System.out.println(MyClass.getCount());    }}Question 3Answera.0b.1c.2d.Compilation error

Question

What is the output of the following code snippet?class MyClass {    static int count = 0;    public MyClass() {        count++;    }    public static int getCount() {        return count;    }}public class Main {    public static void main(String[] args) {        MyClass obj1 = new MyClass();        MyClass obj2 = new MyClass();        System.out.println(MyClass.getCount());    }}Question 3Answera.0b.1c.2d.Compilation error

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Solution

The output of the code snippet will be 2.

Here's the step by step explanation:

  1. The MyClass class has a static variable count which is initialized to 0. Static variables are shared among all instances of a class, meaning all instances of the class have access to the same variable.

  2. The constructor of MyClass increments the count variable by 1 every time a new instance of the class is created.

  3. In the main method of the Main class, two instances of MyClass are created (obj1 and obj2). Each time an instance is created, the constructor of MyClass is called, which increments the count variable by 1.

  4. Therefore, after creating two instances, the count variable will be 2.

  5. The getCount method is a static method that returns the current value of the count variable.

  6. So, when System.out.println(MyClass.getCount()); is executed, it prints the current value of count, which is 2.

So, the correct answer is c.2.

This problem has been solved

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