y=x 2 −x−70y, equals, x, plus, 10y=x+10

It seems like there might be some confusion in the way your equations are written. However, I'll try to interpret them as best as I can.

1. The first equation seems to be y = x^2 - x - 70.
2. The second equation seems to be y = x + 10.

If you want to solve for x and y, you can set the two equations equal to each other because they both equal y:

x^2 - x - 70 = x + 10

To solve for x, you can simplify the equation:

x^2 - x - 80 = 0

This is a quadratic equation, which can be factored to:

(x - 10)(x + 8) = 0

Setting each factor equal to zero gives the solutions x = 10 and x = -8.

Substitute x = 10 into the second equation:

y = 10 + 10 = 20

Substitute x = -8 into the second equation:

y = -8 + 10 = 2

So the solutions to the system of equations are (10, 20) and (-8, 2).

It seems like there might be a misunderstanding with the formatting of your equations. However, I'll try to interpret them as best as I can.

If the equations are:

1. y = x^2 - x - 70
2. y = x + 10

You can solve for x by setting the two equations equal to each other:

x^2 - x - 70 = x + 10

Rearrange the equation to set it equal to zero:

x^2 - 2x - 80 = 0

This is a quadratic equation in the form ax^2 + bx + c = 0. You can solve for x using the quadratic formula x = [-b ± sqrt(b^2 - 4ac)] / (2a):

x = [2 ± sqrt((-2)^2 - 41(-80))] / (2*1) x = [2 ± sqrt(4 + 320)] / 2 x = [2 ± sqrt(324)] / 2 x = [2 ± 18] / 2 x = 20 / 2 or x = -16 / 2 x = 10 or x = -8

So the solutions for x are 10 and -8. You can substitute these values back into the original equations to solve for y.