What is the simplified form of i15?A.1B.-iC.-1D.iSUBMITarrow_backPREVIOUS
Question
What is the simplified form of i15?A.1B.-iC.-1D.iSUBMITarrow_backPREVIOUS
Solution
The simplified form of i^15 can be found by realizing that i, which represents the square root of -1, has a cycle:
i^1 = i, i^2 = -1, i^3 = -i, i^4 = 1, and then the pattern repeats.
So, to simplify i^15, we can divide 15 by 4 (the length of the cycle) and use the remainder to determine the equivalent exponent.
15 divided by 4 is 3 remainder 3.
So, i^15 is equivalent to i^3, which is -i.
So, the answer is B. -i.
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