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Read the statements carefully and answer the questions as directed.Problem 1:A satellite dish is shaped like a paraboloid. If the dish is 2 meters wide and 0.5 meters deep, find the equation of the parabola representing the shape of the dish.*4 pointsy^2 = 4xx^2 = 2yy = x^2/4x^2 = 4yProblem 2:An artist wants to create a fountain with a circular pool. If the pool has a radius of 6 feet, what is the equation of the circle representing the pool?*4 pointsx^2 + y^2 = 6x^2 + y^2 = 36x^2 - y^2 = 36y = √(36-x^2)Problem 3:A company designs a water slide in the shape of a hyperbola. The distance between the vertices is 10 meters, and the distance between the foci is 8 meters. Find the equation of the hyperbola.*4 pointsx^2/25 - y^2/16 = 1y^2/25 - x^2/16 = 1x^2/16 - y^2/25 = 1y^2/16 - x^2/25 = 1Problem 4:A cylindrical tank has an elliptical base with semi-major and semi-minor axes of lengths 8 feet and 5 feet, respectively. Write the equation of the ellipse representing the tank's base.*4 pointsx^2/64 + y^2/25 = 1x^2/25 + y^2/64 = 1x^2 + y^2 = 64x^2/16 + y^2/9 = 1

Question

Read the statements carefully and answer the questions as directed.Problem 1:A satellite dish is shaped like a paraboloid. If the dish is 2 meters wide and 0.5 meters deep, find the equation of the parabola representing the shape of the dish.*4 pointsy^2 = 4xx^2 = 2yy = x^2/4x^2 = 4yProblem 2:An artist wants to create a fountain with a circular pool. If the pool has a radius of 6 feet, what is the equation of the circle representing the pool?*4 pointsx^2 + y^2 = 6x^2 + y^2 = 36x^2 - y^2 = 36y = √(36-x^2)Problem 3:A company designs a water slide in the shape of a hyperbola. The distance between the vertices is 10 meters, and the distance between the foci is 8 meters. Find the equation of the hyperbola.*4 pointsx^2/25 - y^2/16 = 1y^2/25 - x^2/16 = 1x^2/16 - y^2/25 = 1y^2/16 - x^2/25 = 1Problem 4:A cylindrical tank has an elliptical base with semi-major and semi-minor axes of lengths 8 feet and 5 feet, respectively. Write the equation of the ellipse representing the tank's base.*4 pointsx^2/64 + y^2/25 = 1x^2/25 + y^2/64 = 1x^2 + y^2 = 64x^2/16 + y^2/9 = 1

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Solution

Problem 1: The correct equation for the parabola is y^2 = 4x. This is because the dish is 2 meters wide (which is the diameter, so the focus is at 1 meter, or 'a' = 1) and 0.5 meters deep (which is the value of '4a', so 4a = 0.5, hence a = 0.5/4 = 0.125). The standard equation of a parabola is y^2 = 4ax.

Problem 2: The correct equation for the circle is x^2 + y^2 = 36. This is because the radius of the pool is 6 feet, and the standard equation of a circle is x^2 + y^2 = r^2, where r is the radius.

Problem 3: The correct equation for the hyperbola is x^2/25 - y^2/16 = 1. This is because the distance between the vertices (which is 2a) is 10 meters, so a = 5, and the distance between the foci (which is 2c) is 8 meters, so c = 4. The relationship between a, b, and c in a hyperbola is c^2 = a^2 + b^2. Solving for b, we get b = sqrt(c^2 - a^2) = sqrt(16 - 25) = sqrt(9) = 3. The standard equation of a hyperbola is x^2/a^2 - y^2/b^2 = 1.

Problem 4: The correct equation for the ellipse is x^2/64 + y^2/25 = 1. This is because the semi-major axis is 8 feet (so a = 8, and a^2 = 64) and the semi-minor axis is 5 feet (so b = 5, and b^2 = 25). The standard equation of an ellipse is x^2/a^2 + y^2/b^2 = 1.

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Similar Questions

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A water fountain is designed to shoot a stream of water in the shape of a parabolic arc. The equation of the parabola is given by ℎ(𝑡)=−0.5𝑡2+4𝑡+1h(t)=−0.5t 2 +4t+1, where ℎ(𝑡)h(t) represents the height of the water stream in meters and t  represents the time in seconds since the water was shot. Answer the following questions.Determine the maximum height reached (in meters).

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Sunita had a hemispherical bowl of radius 𝑟.She made a conical vessel of radius 𝑟 with a tinsheet.(i) find the height of the conical vessel so that it canhold the water same as that of the hemisphericalbowl.(ii) If the radius of the cone formed in the above part is 14 cm, then find how much sheet isused?(iii) If the height of the conical vessel is doubled, how much more water can it hold than thehemispherical bowl?

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