The JCR of a student hostel is 50.0 ft long and 26 ftwide and has 8.0-ft high ceilings. What is the volume of theinterior of the room in cubic centimeters? [1 ft = 0.304 8 m]
Question
The JCR of a student hostel is 50.0 ft long and 26 ftwide and has 8.0-ft high ceilings. What is the volume of theinterior of the room in cubic centimeters? [1 ft = 0.304 8 m]
Solution
To find the volume of the room in cubic centimeters, we first need to convert the dimensions from feet to meters, and then from meters to centimeters.
Step 1: Convert the dimensions from feet to meters
- Length: 50.0 ft * 0.3048 m/ft = 15.24 m
- Width: 26 ft * 0.3048 m/ft = 7.9256 m
- Height: 8.0 ft * 0.3048 m/ft = 2.4384 m
Step 2: Convert the dimensions from meters to centimeters
- Length: 15.24 m * 100 cm/m = 1524 cm
- Width: 7.9256 m * 100 cm/m = 792.56 cm
- Height: 2.4384 m * 100 cm/m = 243.84 cm
Step 3: Calculate the volume in cubic centimeters
- Volume = Length * Width * Height = 1524 cm * 792.56 cm * 243.84 cm = 294,680,000,000 cubic centimeters.
Similar Questions
A room in a house has a floor area of 160 ft2. Which of the following is most likely the approximate volume of the room?Select one:a.4 m3b.4000 m3c.400 m3d.40 m3
Jackson has a wardrobe with two compartments shaped like rectangular prisms. What is the volume of his wardrobe? A. 288 cubic feet B. 144 cubic feet C. 48 cubic feet D. 168 cubic feet
Suppose you have a rectangular room 20 ft by 18 ft. What is the area of this room in square metres?(Carry 4 decimals throughout the calculation and round your answer to one decimal. Do not enter any units in the blank.)
A single room self-contained in a Bilsi Hostel is advertised as having 144 square feet under its roof. What is the area of the room in square meters? [1𝘮≡ 3.28 𝘧𝘵]1 point472.32 m²1549.21 m²13.38 m²43.90 m²
Q.3: The length, breadth and height of a room are 5 m, 4 m and 3 m respectively. Find the cost of whitewashing the walls of the room and the ceiling at the rate of Rs.7.50 per sq.m.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.