Two buses started from the same point and at the same time. The first bus is going in the east direction at 10 KMPH and the second bus is going towards the north direction at a speed of 24 KMPH. How far will the two cars will be from each other after 3 hrs
Question
Two buses started from the same point and at the same time. The first bus is going in the east direction at 10 KMPH and the second bus is going towards the north direction at a speed of 24 KMPH. How far will the two cars will be from each other after 3 hrs
Solution
Sure, here's how you can solve this problem:
Step 1: Calculate the distance covered by each bus after 3 hours.
For the first bus going east at 10 KMPH, the distance covered would be speed * time = 10 KMPH * 3 hours = 30 KM.
For the second bus going north at 24 KMPH, the distance covered would be speed * time = 24 KMPH * 3 hours = 72 KM.
Step 2: Now, we have a right triangle where the distance covered by the first bus is one side (30 KM), the distance covered by the second bus is the other side (72 KM), and the distance between the two buses is the hypotenuse which we need to find.
Step 3: Use the Pythagorean theorem to find the hypotenuse. The theorem states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
So, the distance between the two buses = sqrt((30 KM)^2 + (72 KM)^2) = sqrt(900 + 5184) = sqrt(6084) = approximately 78 KM.
So, the two buses will be approximately 78 KM apart from each other after 3 hours.
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