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Students put animal cells into two different strengths of sugar solutions, A and B.The diagram below shows what the cells looked like after 1 hour.Describe one way in which the cell in sugar solution B is different from the cell in sugar solution A.Cell B has lost water and burst.Cell B has gained water and shrivelled up.Cell B has lost water and shrivelled up.Cell B has gained water and burst.I DON'T KNOWSUBMIT ANSWER

Question

Students put animal cells into two different strengths of sugar solutions, A and B.The diagram below shows what the cells looked like after 1 hour.Describe one way in which the cell in sugar solution B is different from the cell in sugar solution A.Cell B has lost water and burst.Cell B has gained water and shrivelled up.Cell B has lost water and shrivelled up.Cell B has gained water and burst.I DON'T KNOWSUBMIT ANSWER

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Solution

The question seems to be incomplete as there is no diagram provided. However, based on the options given, it seems like the question is about osmosis in animal cells.

Osmosis is the process where water moves from an area of low solute concentration to an area of high solute concentration. In the context of cells, if a cell is in a solution with a higher sugar concentration (hypertonic solution), water will move out of the cell causing it to shrivel up. On the other hand, if a cell is in a solution with a lower sugar concentration (hypotonic solution), water will move into the cell causing it to burst.

Without the diagram, it's hard to definitively answer the question. However, if we assume that solution B has a higher sugar concentration than solution A, then the cell in solution B would have lost water and shrivelled up. If solution B has a lower sugar concentration than solution A, then the cell in solution B would have gained water and burst.

This problem has been solved

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