A 14.0-g bullet is fired into a 1,100-g block of wood which is suspended as a ballistic pendulum. The combined mass swings up to a height of 8.50 cm. What was the kinetic energy of the combined mass immediately after the collision?Select one:a.0.928 Jb.0.095 Jc.0.012 Jd.0.928 × 103 Je.0.916 J
Question
A 14.0-g bullet is fired into a 1,100-g block of wood which is suspended as a ballistic pendulum. The combined mass swings up to a height of 8.50 cm. What was the kinetic energy of the combined mass immediately after the collision?Select one:a.0.928 Jb.0.095 Jc.0.012 Jd.0.928 × 103 Je.0.916 J
Solution
To solve this problem, we need to use the principle of conservation of energy. The kinetic energy immediately after the collision is converted into potential energy at the highest point of the swing.
The potential energy (PE) at the highest point of the swing can be calculated using the formula:
PE = mgh
where: m is the total mass (bullet + block of wood) = (14 g + 1100 g) = 1114 g = 1.114 kg (since 1 kg = 1000 g) g is the acceleration due to gravity = 9.8 m/s² h is the height = 8.50 cm = 0.085 m (since 1 m = 100 cm)
Substituting these values into the formula gives:
PE = 1.114 kg * 9.8 m/s² * 0.085 m = 0.928 Joules
Therefore, the kinetic energy of the combined mass immediately after the collision was 0.928 Joules. So, the correct answer is a. 0.928 J.
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