f(x)=x^2-25 g(x)=x+4solve fg(x+1)=gf(x)
Question
f(x)=x^2-25 g(x)=x+4solve fg(x+1)=gf(x)
Solution
First, let's find the expressions for fg(x) and gf(x).
fg(x) is the composition of f and g, which means we apply g first and then f. So, fg(x) = f(g(x)).
Given g(x) = x + 4, then g(x+1) = (x+1) + 4 = x + 5.
So, fg(x+1) = f(g(x+1)) = f(x+5) = (x+5)^2 - 25.
Similarly, gf(x) is the composition of g and f, which means we apply f first and then g. So, gf(x) = g(f(x)).
Given f(x) = x^2 - 25, then f(x) = x^2 - 25.
So, gf(x) = g(f(x)) = g(x^2 - 25) = (x^2 - 25) + 4 = x^2 - 21.
The equation fg(x+1) = gf(x) becomes (x+5)^2 - 25 = x^2 - 21.
Solving this equation, we get:
(x+5)^2 - x^2 = 4 x^2 + 10x + 25 - x^2 = 4 10x + 25 = 4 10x = -21 x = -21/10 = -2.1
So, the solution to the equation fg(x+1) = gf(x) is x = -2.1.
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