If the equations 28x + 16y + 10 = 0 and 42x - ky - 14 = 0 have no solution, then the value of k is:
Question
If the equations 28x + 16y + 10 = 0 and 42x - ky - 14 = 0 have no solution, then the value of k is:
Solution
Two linear equations will have no solution if and only if the lines represented by them are parallel. Two lines are parallel if their slopes are equal.
The slope-intercept form of a linear equation is y = mx + c, where m is the slope.
Let's convert the given equations into slope-intercept form:
- 28x + 16y + 10 = 0 can be rewritten as y = -(28/16)x - 10/16 = -7/4x - 5/8
So, the slope (m1) of the first line is -7/4.
- 42x - ky - 14 = 0 can be rewritten as y = (42/k)x + 14/k
So, the slope (m2) of the second line is 42/k.
For the lines to be parallel, m1 must be equal to m2. Therefore, we set the two slopes equal to each other and solve for k:
-7/4 = 42/k
Cross-multiplying gives -7k = 168
So, k = 168 / -7 = -24
Therefore, the value of k for which the two equations have no solution is -24.
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