If \ cosθ=−13 \ and \ π/2≤θ≤π, \ then sinθ=

To find the value of sinθ, we can use the Pythagorean identity for sine and cosine, which is sin²θ + cos²θ = 1.

Given that cosθ = -13, we can substitute this into the identity:

sin²θ + (-13)² = 1 sin²θ + 169 = 1 sin²θ = 1 - 169 sin²θ = -168

However, this result is not possible because the square of a real number cannot be negative. Therefore, there seems to be a mistake in the problem. The value of cosθ should be between -1 and 1 for real θ. So, cosθ = -13 is not possible. Please check the problem again.