If for a distribution the difference of first quartile and median is greater than difference of median and third quartile then the distribution is classified as*1 pointnot skewed at allabsolute open endedpositively skewednegatively skewed
Question
If for a distribution the difference of first quartile and median is greater than difference of median and third quartile then the distribution is classified as*1 pointnot skewed at allabsolute open endedpositively skewednegatively skewed
Solution
The distribution is classified as negatively skewed.
Here's why:
In a negatively skewed distribution, the majority of the data points fall to the right of the mean (higher values), with the tail of the distribution stretching out to the left (lower values).
The first quartile (Q1) represents the 25th percentile of the data, and the third quartile (Q3) represents the 75th percentile. The median (Q2) is the 50th percentile.
If the difference between Q1 and the median is greater than the difference between the median and Q3, it means that the lower half of the data (from the minimum to the median) is more spread out than the upper half (from the median to the maximum). This is characteristic of a negatively skewed distribution.
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