If we had added straws under the block to roll on - what do you think would have happened to the amount of force needed to move the block?  Why?

When did the block move with the least amount of force?

A 10 kg block is placed on a horizontal surface whose coefficient of friction is 0.25. A horizontal force P = 15 N first acts on it in the eastward direction. Later, in addition to P a second horizontal force Q = 20 N acts on it in the northward direction : (Both east and west are in the plane of the fig and the gravity acts perpendicular to this plane )The block will not move when only P acts, but will be about to move when both P and Q actIf the block moves, the acceleration will be 0.5 m/s2.When the block moves, its direction of motion will be   (4/3) east of north When both P and Q act, the direction of the force of friction acting on the block will be   (3/4) west of      south

two stationary blocks—one on ice, and one on gravel. It is easier to push a block on ice than it is to push a block on gravel. Apply your knowledge of inertia and Newton's First Law of Motion to explain why.

In the diagram below, the same small horizontal force is applied to blocks "A" and "B", however, block "A" generates a greater friction force than block "B". Question 16Select one:TrueFalse

A block with mass m1 = 0.400 kg is released from rest on a frictionless track at a distance h1 = 3.00 m above the top of a table. It then collides elastically with an object having mass m2 = 0.800 kg that is initially at rest on the table, as shown in the figure below.A curved wedge rests on a table. The wedge has the appearance of a hill sliced vertically in half: the surface at the top is horizontal, and then it gradually increases the magnitude of its slope down to the right before turning sharply down, and then decreasing the magnitude of its slope until it is almost horizontal. The vertical distance between the surface of the table and the top of the wedge is h1. The height of the table is h2. A block labeled m1 rests on the top of the wedge. A block labeled m2 rests at the very bottom of the slope of the wedge, at the edge of the table. A dashed parabolic line shows the path m2 would take after being knocked off the table. The path ends a horizontal distance x from the edge of the table.(a) Determine the velocities of the two objects just after the collision. (Assume the positive direction is to the right. Indicate the direction with the signs of your answers.)v1 = m/sv2 = m/s(b) How high up the track does the 0.400-kg object travel back after the collision? m(c) How far away from the bottom of the table does the 0.800-kg object land, given that the height of the table is h2 = 1.95 m? m(d) How far away from the bottom of the table does the 0.400-kg object eventually land? m