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Which expression gives the mass, in g, of ethanol required to produce 683.5 kJ of heat upon complete combustion?(Mr for ethanol = 46.0, ΔHθc=−1367 kJmol−1Δ𝐻𝑐𝜃=−1367 kJmol−1)A.     683.51367×46.0683.51367×46.0B.     1367683.5×46.01367683.5×46.0C.     683.5×46.01367683.5×46.01367D.     1367×46.0683.51367×46.0683.5

Question

Which expression gives the mass, in g, of ethanol required to produce 683.5 kJ of heat upon complete combustion?(Mr for ethanol = 46.0, ΔHθc=−1367 kJmol−1Δ𝐻𝑐𝜃=−1367 kJmol−1)A.     683.51367×46.0683.51367×46.0B.     1367683.5×46.01367683.5×46.0C.     683.5×46.01367683.5×46.01367D.     1367×46.0683.51367×46.0683.5

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Solution

The heat of combustion (ΔHθc) is the heat released when one mole of a substance is completely burned in excess oxygen. It is given as -1367 kJ/mol for ethanol. This means that 1367 kJ of heat is released when 46.0 g (1 mol) of ethanol is burned.

We are asked to find the mass of ethanol that would release 683.5 kJ of heat. We can set up a proportion to solve this:

1367 kJ is to 46.0 g as 683.5 kJ is to x g.

Solving for x gives us the mass of ethanol required to produce 683.5 kJ of heat.

So, the correct expression is:

x = (683.5 kJ / 1367 kJ) * 46.0 g

This corresponds to option A: 683.5/1367 * 46.0.

This problem has been solved

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