The molar conductance of 0.001M acetic acid is 50 ohm-1 cm2 mol-1 . The maximum value of molarconductance is 250 ohm-1 cm2 mol-1 . What is its degree of ionisation?
Question
The molar conductance of 0.001M acetic acid is 50 ohm-1 cm2 mol-1 . The maximum value of molarconductance is 250 ohm-1 cm2 mol-1 . What is its degree of ionisation?
Solution
The degree of ionisation (α) can be calculated using the formula:
α = Λm/Λ°m
where: Λm is the molar conductance of the solution, and Λ°m is the maximum molar conductance (at infinite dilution).
Given in the problem: Λm = 50 ohm-1 cm2 mol-1 Λ°m = 250 ohm-1 cm2 mol-1
Substituting these values into the formula:
α = 50/250 = 0.2
Therefore, the degree of ionisation of the 0.001M acetic acid solution is 0.2 or 20%.
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