In 2001, the polls found that 81% of American adults believed that there was a conspiracy in the death of President Kennedy. Assume a recent poll asked 1740 American adults if they believe there was a conspiracy in the assassination and it found that 1374 believe there was a conspiracy. Does the data show that the proportion of Americans who believe in this conspiracy is now lower? Test at the 5% level.P: PARAMETER     What is the correct parameter symbol for this problem?          What is the wording of the parameter in the context of this problem?     H: HYPOTHESES     Fill in the correct null and alternative hypotheses:     𝐻0:      𝐻𝐴: A: ASSUMPTIONS     Since information was collected from each object, what conditions do we need to check?     Check all that apply.     𝑛(𝑝̂)≥10𝑁≥20𝑛𝑛𝑝≥10𝑛(1-𝑝)≥10𝑛(1-𝑝̂)≥10σσ is known.𝑛≥30 or normal population.σσ is unknown.     Check those assumptions:          1. 𝑛𝑝 = which is           2. 𝑛(1-𝑝) = which is           3. 𝑁 = which is               If no N is given in the problem, use 1000000N: NAME THE PROCEDURE     The conditions are met to use a .T: TEST STATISTIC     The symbol and value of the random variable on this problem are as follows:     Leave this answer as a fraction.     =      The formula set up of the test statistic is as follows.:       (Leave any values that were given as fractions as fractions) 𝑧=𝑝̂-𝑝𝑝(1-𝑝)𝑛=( - )/(( ⋅(1- )) / )       Final answer for the test statistic from technology.     Round to 2 decimal places:     z = O: OBTAIN THE P-VALUE     Report to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = M: MAKE A DECISION     Since the p-value , we .S: STATE A CONCLUSION    There significant evidence to conclude

In July of 2013, Australians were asked if they thought unemployment would increase, and 47% thought that it would increase. In November of 2013, they were asked again. At that time 570 out of 1300 said that they thought unemployment would increase. At the 8% level, is there enough evidence to show that the proportion of Australians in November 2013 who believe unemployment would increase is lower than the proportion who felt it would increase in July 2013?P: PARAMETER     What is the correct parameter symbol for this problem?     Correct     What is the wording of the parameter in the context of this problem?     CorrectH: HYPOTHESES     Fill in the correct null and alternative hypotheses:     𝐻0: Correct Correct .47Correct     𝐻𝐴: Correct Correct .47CorrectA: ASSUMPTIONS     Since Correct information was collected from each object, what conditions do we need to check?     Check all that apply.     𝑛≥30 or normal population.𝑛(𝑝̂)≥10𝑁≥20𝑛σσ is known.𝑛(1-𝑝̂)≥10𝑛𝑝≥10σσ is unknown.𝑛(1-𝑝)≥10Partially correct     Check those assumptions:          1. 𝑛𝑝 = 611Correct which is Correct 10Correct          2. 𝑛(1-𝑝) = 689Correct which is Correct 10Correct          3. 𝑁 = 1000000Correct which is Correct 1300Incorrect              If no N is given in the problem, use 1000000N: NAME THE PROCEDURE     The conditions are met to use a Correct .T: TEST STATISTIC     The symbol and value of the random variable on this problem are as follows:     Leave this answer as a fraction.     Incorrect = 5701300​Correct      The formula set up of the test statistic is as follows.:       (Leave any values that were given as fractions as fractions) 𝑧=𝑝̂-𝑝𝑝(1-𝑝)𝑛=( 5701300​Correct -.47Correct )/((.47Correct ⋅(1-.47Correct )) /1300Correct )       Final answer for the test statistic from technology.     Round to 2 decimal places:     z = −2.08IncorrectO: OBTAIN THE P-VALUE     Report to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = .0148IncorrectM: MAKE A DECISION     Since the p-value .08Correct , we Correct .S: STATE A CONCLUSION    There Correct significant evidence to conclude Incorrect Correct

In July of 2013, 47% of Australians thought unemployment would increase.  Assume in a recent poll, 140 out of 300 said that they thought unemployment would increase.  Estimate the proportion of all Australians today who believe unemployment would increase using a 98% confidence interval.P: Parameter    What is the correct parameter symbol for this problem?        What is the wording of the parameter in the context of this problem?    A: AssumptionsSince information was collected from each object, what conditions do we need to check?  Check all that apply.   𝑛≥30 or normal population.𝑁≥20𝑛𝑛(1-𝑝̂)≥10𝑛𝑝≥10σσ is known.𝑛(1-𝑝)≥10σσ is unknown.𝑛(𝑝̂)≥10    Check those assumptions:    1. 𝑛𝑝^= which is     2. 𝑛(1-𝑝^)= which is     3. 𝑁= which is          If no N is given in the problem, use 1000000N: Name the procedure     The conditions are met to use a .I: Interval and point estimate    The symbol and value of the point estimate on this problem are as follows:    = Leave answer as a fraction.    The interval estimate for is ( , )    Round endpoints to 3 decimal places.C: Conclusion We are % confident that the is between % and %

According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 2007 were for identity theft. In that year, assume some state had 422 complaints of identity theft out of 1550 consumer complaints. Do these data provide enough evidence to show that that state had a higher proportion of identity theft than 23%? Test at the 9% level.P: PARAMETER     What is the correct parameter symbol for this problem?          What is the wording of the parameter in the context of this problem?     H: HYPOTHESES     Fill in the correct null and alternative hypotheses:     𝐻0:      𝐻𝐴: A: ASSUMPTIONS     Since information was collected from each object, what conditions do we need to check?     Check all that apply.     𝑁≥20𝑛σσ is unknown.𝑛𝑝≥10𝑛(𝑝̂)≥10σσ is known.𝑛(1-𝑝)≥10𝑛(1-𝑝̂)≥10𝑛≥30 or normal population.     Check those assumptions:          1. 𝑛𝑝 = which is           2. 𝑛(1-𝑝) = which is           3. 𝑁 = which is               If no N is given in the problem, use 1000000N: NAME THE PROCEDURE     The conditions are met to use a .T: TEST STATISTIC     The symbol and value of the random variable on this problem are as follows:     Leave this answer as a fraction.     =      The formula set up of the test statistic is as follows.:       (Leave any values that were given as fractions as fractions) 𝑧=𝑝̂-𝑝𝑝(1-𝑝)𝑛=( - )/(( ⋅(1- )) / )       Final answer for the test statistic from technology.     Round to 2 decimal places:     z = O: OBTAIN THE P-VALUE     Report to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = M: MAKE A DECISION     Since the p-value , we .S: STATE A CONCLUSION    There significant evidence to conclude

It is believed that 11% of all Americans are left-handed. A college needs to know how many left-handed desks to place in the big lecture halls being constructed on its campus. In a random sample of 100 students of its 10376 students, 14 were left-handed. Does this provide enough evidence to show that students at this college have a higher percentage of left-handers than the general American population? Use a 10% level of significance.P: PARAMETER     What is the correct parameter symbol for this problem?          What is the wording of the parameter in the context of this problem?     H: HYPOTHESES     Fill in the correct null and alternative hypotheses:     𝐻0:      𝐻𝐴: A: ASSUMPTIONS     Since information was collected from each object, what conditions do we need to check?     Check all that apply.     σσ is unknown.𝑛(1-𝑝)≥10σσ is known.𝑛(1-𝑝̂)≥10𝑛(𝑝̂)≥10𝑛𝑝≥10𝑛≥30 or normal population.𝑁≥20𝑛     Check those assumptions:          1. 𝑛𝑝 = which is           2. 𝑛(1-𝑝) = which is           3. 𝑁 = which is               If no N is given in the problem, use 1000000N: NAME THE PROCEDURE     The conditions are met to use a .T: TEST STATISTIC     The symbol and value of the random variable on this problem are as follows:     Leave this answer as a fraction.     =      The formula set up of the test statistic is as follows.:       (Leave any values that were given as fractions as fractions) 𝑧=𝑝̂-𝑝𝑝(1-𝑝)𝑛=( - )/(( ⋅(1- )) / )       Final answer for the test statistic from technology.     Round to 2 decimal places:     z = O: OBTAIN THE P-VALUE     Report to 4 decimal places.     It is possible when rounded that a p-value is 0.0000     P-value = M: MAKE A DECISION     Since the p-value , we .S: STATE A CONCLUSION    There significant evidence to conclude

In each of the following examples, a test for the population proportion (p) is called for. You are asked to select the right null and alternative hypotheses.Scenario 1: The UCLA Internet Report (February 2003) estimated that roughly 8.7% of Internet users are extremely concerned about credit card fraud when buying online. Has that figure changed since? To test this, a random sample of 100 Internet users was chosen, and when interviewed, 10 said that they were extremely worried about credit card fraud when buying online. Let p be the proportion of all Internet users who are concerned about credit card fraud.The null hypothesis in this case is:H0: p = 8.7H0: p = 0.087H0: p = 0.10H0: p ≠ 0.087H0: p > 0.087The alternative hypothesis in this case is:Ha: p > 0.087Ha: p < 0.087Ha: p ≠ 0.087Ha: p = 0.087Reset this ActivityScenario 2: The UCLA Internet Report (February 2003) estimated that a proportion of roughly .75 of online homes are still using dial-up access, but claimed that the use of dial-up is declining. Is that really the case? To examine this, a follow-up study was conducted a year later in which out of a random sample of 1,308 households that had Internet access, 804 were connecting using a dial-up modem. Let p be the proportion of all U.S. Internet-using households that have dial-up access.The null hypothesis in this case is:H0: p = 0.75H0: p = 0.615H0: p < 0.75H0: p > 0.615The alternative hypothesis in this case is:Ha: p > 0.75Ha: p < 0.75Ha: p ≠ 0.75Ha: p < 0.615