There are three fractions A, B and C. If A = 1/6 and B = 1/8 and the average of A, B and C is 1/16 . What is the value of C?​Question Description : -11/48-11/32-12/32-12/48

To find the value of C, we first need to understand that the average of three numbers is the sum of those numbers divided by 3.

Given that the average of A, B, and C is 1/16, we can write this equation:

(A + B + C) / 3 = 1/16

We know the values of A and B, so we can substitute those in:

(1/6 + 1/8 + C) / 3 = 1/16

To simplify the equation, we first need to find a common denominator for 1/6 and 1/8. The least common multiple of 6 and 8 is 24, so we convert the fractions:

(4/24 + 3/24 + C) / 3 = 1/16

Adding the fractions gives us:

(7/24 + C) / 3 = 1/16

We can multiply both sides of the equation by 3 to isolate the fraction with C:

7/24 + C = 3/16

To isolate C, we subtract 7/24 from both sides of the equation:

C = 3/16 - 7/24

Again, we need to find a common denominator for these fractions. The least common multiple of 16 and 24 is 48, so we convert the fractions:

C = 9/48 - 14/48

Subtracting the fractions gives us:

C = -5/48

So, none of the options provided are correct. The value of C is -5/48.