What is the probability of getting 3 heads if 6 unbaised coins are tossed simultaneously ?(a) 0.3125(b) 0.25(c) 0.6825(d) 0.50

To find the probability of getting 3 heads when 6 unbiased coins are tossed simultaneously, we can use the concept of binomial probability.

Step 1: Determine the number of possible outcomes. Since each coin can either land on heads or tails, there are 2 possible outcomes for each coin. Therefore, the total number of possible outcomes for 6 coins is 2^6 = 64.

Step 2: Determine the number of favorable outcomes. To get 3 heads, we need to choose 3 out of the 6 coins to land on heads. This can be calculated using the combination formula: C(6, 3) = 6! / (3! * (6-3)!) = 20.

Step 3: Calculate the probability. The probability of getting 3 heads is equal to the number of favorable outcomes divided by the number of possible outcomes: P(3 heads) = 20/64 = 0.3125.

Therefore, the correct answer is (a) 0.3125.