Which of the following oxidation states of Rhenium could exhibit greatest paramagnetism.Assume all in low spin octahedral complexes.a. Re(II)b. Re(IV)c. Re(VI)d. Re(I)e. Re(V)

The paramagnetism of a substance is directly related to the number of unpaired electrons in its atomic or molecular orbitals. The more unpaired electrons, the greater the paramagnetism.

Rhenium (Re) has an atomic number of 75, which means its electron configuration ends in 5d5 6s2 in its ground state.

When it forms an octahedral complex, the 6s electrons are usually first to be removed, followed by the 5d electrons.

a. Re(II) would have an electron configuration of [Xe] 4f14 5d3, which means it has 3 unpaired electrons. b. Re(IV) would have an electron configuration of [Xe] 4f14 5d1, which means it has 1 unpaired electron. c. Re(VI) would have an electron configuration of [Xe] 4f14, which means it has no unpaired electrons. d. Re(I) would have an electron configuration of [Xe] 4f14 5d4, which means it has 4 unpaired electrons. e. Re(V) would have an electron configuration of [Xe] 4f14 5d2, which means it has 2 unpaired electrons.

Therefore, Re(I) would exhibit the greatest paramagnetism as it has the most unpaired electrons.