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Find the sum of the terms of the arithmetic progression whose first term, last term and common difference are 3, 101 and 7 respectively.a.810b.720c.750d.780

Question

Find the sum of the terms of the arithmetic progression whose first term, last term and common difference are 3, 101 and 7 respectively.a.810b.720c.750d.780

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Solution

To find the sum of the terms of an arithmetic progression, we can use the formula:

Sum = n/2 * (a + l)

where: n = number of terms a = first term l = last term

First, we need to find the number of terms (n). We can use the formula:

n = ((l - a) / d) + 1

where: l = last term = 101 a = first term = 3 d = common difference = 7

Substituting the values, we get:

n = ((101 - 3) / 7) + 1 = 14 + 1 = 15

Now, we can find the sum:

Sum = 15/2 * (3 + 101) = 7.5 * 104 = 780

So, the sum of the terms of the arithmetic progression is 780 (option d).

This problem has been solved

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