8. If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s, what's the acceleration of the object? A. 5.42 m/s B. 13.58 m/s OC. 2.75 m/s OD. 33 m/s
Question
- If the velocity of an object changes from 65 m/s to 98 m/s during a time interval of 12 s, what's the acceleration of the object? A. 5.42 m/s B. 13.58 m/s OC. 2.75 m/s OD. 33 m/s
Solution
The acceleration of an object can be calculated using the formula:
Acceleration = (Final velocity - Initial velocity) / Time
Here, the final velocity is 98 m/s, the initial velocity is 65 m/s, and the time is 12 s.
So, the acceleration is (98 m/s - 65 m/s) / 12 s = 33 m/s / 12 s = 2.75 m/s.
Therefore, the correct answer is C. 2.75 m/s.
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