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If it is possible to make a three-digit number, which is a perfect square of a two-digit number from the second, the fourth and the eight digits of 31792056, using each digit only once, what is the two-digit number? If the perfect square cannot be formed, your answer is ‘N’ and if more than one such numbers can be formed, your answer is ‘X’

Question

If it is possible to make a three-digit number, which is a perfect square of a two-digit number from the second, the fourth and the eight digits of 31792056, using each digit only once, what is the two-digit number? If the perfect square cannot be formed, your answer is ‘N’ and if more than one such numbers can be formed, your answer is ‘X’

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Solution

The second, fourth, and eighth digits of the number 31792056 are 1, 9, and 5 respectively.

We can rearrange these digits to form the numbers 195, 159, 519, 591, 915, and 951.

We need to check if any of these numbers is a perfect square of a two-digit number.

The two-digit numbers range from 10 to 99. The squares of these numbers range from 100 (10^2) to 9801 (99^2).

None of the numbers we formed (195, 159, 519, 591, 915, and 951) fall within this range.

Therefore, it is not possible to form a three-digit perfect square of a two-digit number using the second, fourth, and eighth digits of 31792056.

So, the answer is 'N'.

This problem has been solved

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