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A student wants to generate a square wave with 50% duty cycle and 1K Hz frequency using 555 timer IC. What is the value of external resistance(s) (in Ohm)? (C = 0.01micro-Farads) a. 15.9K b. 100K c. 50K d. 72.46K

Question

A student wants to generate a square wave with 50% duty cycle and 1K Hz frequency using 555 timer IC. What is the value of external resistance(s) (in Ohm)? (C = 0.01micro-Farads)

a. 15.9K

b. 100K

c. 50K

d. 72.46K

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Solution

The 555 timer IC can be used to generate a square wave of a specific frequency. The frequency of the output square wave is determined by the values of two resistors (R1 and R2) and one capacitor (C). The formula to calculate the frequency is:

f = 1.44 / ((R1 + 2R2) * C)

Given that the frequency (f) is 1KHz and the capacitor (C) is 0.01 microfarads, we can rearrange the formula to solve for the resistance:

R1 + 2R2 = 1.44 / (f * C)

Substituting the given values:

R1 + 2R2 = 1.44 / (1000 * 0.01 * 10^-6)

R1 + 2R2 = 144,000 Ohms

Assuming a 50% duty cycle, R1 and R2 should be equal (R1 = R2). Therefore, we can divide the total resistance by 3 to find the value of each resistor:

R1 = R2 = 144,000 / 3 = 48,000 Ohms

So, the value of the external resistances is not listed in the options provided. There might be a mistake in the question or the options.

This problem has been solved

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