Tyler slides across his kitchen floor. The coefficient of kinetic friction between his socks and the tile is 0.3. If his mass is 67 kg, what is the force of friction acting on him?A.197 NB.657 NC.421 ND.102 N
Question
Tyler slides across his kitchen floor. The coefficient of kinetic friction between his socks and the tile is 0.3. If his mass is 67 kg, what is the force of friction acting on him?A.197 NB.657 NC.421 ND.102 N
Solution
To solve this problem, we need to use the formula for the force of friction, which is:
F = μN
where: F is the force of friction, μ is the coefficient of kinetic friction, and N is the normal force.
In this case, the normal force is equal to the weight of Tyler, which is his mass times the acceleration due to gravity. On Earth, the acceleration due to gravity is approximately 9.8 m/s². So, the normal force is:
N = m*g N = 67 kg * 9.8 m/s² N = 656.6 N
Now we can calculate the force of friction:
F = μN F = 0.3 * 656.6 N F = 196.98 N
So, the force of friction acting on Tyler is approximately 197 N. Therefore, the correct answer is A.197 N.
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