When 24.0 × 1013 electrons are transferred from one plate of a capacitor to another plate under apotential difference of 16 V, calculate the capacitance of the capacitor
Question
When 24.0 × 1013 electrons are transferred from one plate of a capacitor to another plate under apotential difference of 16 V, calculate the capacitance of the capacitor
Solution
To calculate the capacitance of the capacitor, we can use the formula:
C = Q/V
where: C is the capacitance, Q is the charge, and V is the potential difference.
First, we need to calculate the charge (Q). The charge of one electron is approximately -1.6 x 10^-19 Coulombs. So, the total charge transferred would be:
Q = number of electrons * charge of one electron Q = 24.0 x 10^13 * -1.6 x 10^-19 Q = -3.84 Coulombs
Note: The charge is negative because electrons carry a negative charge.
Next, we substitute Q and V into the formula:
C = Q/V C = -3.84/-16 C = 0.24 Farads
So, the capacitance of the capacitor is 0.24 Farads.
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