The population of a village was 9800. In a year, with the increase in population of males by 8% and that of females by 5%, the population of the village became 10,458.What was the number of males in the village before increase?Options4,2004,4106,0485,600
Question
The population of a village was 9800. In a year, with the increase in population of males by 8% and that of females by 5%, the population of the village became 10,458.What was the number of males in the village before increase?Options4,2004,4106,0485,600
Solution
Let's denote the initial number of males as M and the initial number of females as F. We know that:
M + F = 9800 (1) (This is the initial total population)
After a year, the population of males increased by 8% and the population of females increased by 5%, making the total population 10458. This gives us another equation:
M * 1.08 + F * 1.05 = 10458 (2) (This is the population after the increase)
We now have a system of two equations, and we can solve it step by step.
First, let's express F from equation (1):
F = 9800 - M
Now we can substitute F in equation (2):
M * 1.08 + (9800 - M) * 1.05 = 10458
Let's simplify this equation:
1.08M + 10290 - 1.05M = 10458
This simplifies to:
0.03M = 168
Finally, we can find M by dividing both sides of the equation by 0.03:
M = 168 / 0.03 = 5600
So, the number of males in the village before the increase was 5600.
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