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The population of a village was 9800. In a year, with the increase in population of males by 8% and that of females by 5%, the population of the village became 10,458.What was the number of males in the village before increase?Options4,2004,4106,0485,600

Question

The population of a village was 9800. In a year, with the increase in population of males by 8% and that of females by 5%, the population of the village became 10,458.What was the number of males in the village before increase?Options4,2004,4106,0485,600

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Solution

Let's denote the initial number of males as M and the initial number of females as F. We know that:

M + F = 9800 (1) (This is the initial total population)

After a year, the population of males increased by 8% and the population of females increased by 5%, making the total population 10458. This gives us another equation:

M * 1.08 + F * 1.05 = 10458 (2) (This is the population after the increase)

We now have a system of two equations, and we can solve it step by step.

First, let's express F from equation (1):

F = 9800 - M

Now we can substitute F in equation (2):

M * 1.08 + (9800 - M) * 1.05 = 10458

Let's simplify this equation:

1.08M + 10290 - 1.05M = 10458

This simplifies to:

0.03M = 168

Finally, we can find M by dividing both sides of the equation by 0.03:

M = 168 / 0.03 = 5600

So, the number of males in the village before the increase was 5600.

This problem has been solved

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