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When digits of a first two-digit number are reversed, then the resulting number will become 75% of second two-digit number. The difference of squares of tens digit and units digit of the second number is 20. Find the first number.

Question

When digits of a first two-digit number are reversed, then the resulting number will become 75% of second two-digit number. The difference of squares of tens digit and units digit of the second number is 20. Find the first number.

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Solution

Let's break down the problem step by step:

Step 1: Let's assume the first two-digit number is represented as "AB", where A is the tens digit and B is the units digit.

Step 2: According to the problem, when the digits of the first number are reversed, the resulting number becomes 75% of the second two-digit number. This can be represented as:

(10B + A) = 0.75 * (10A + B)

Step 3: Simplifying the equation, we get:

10B + A = 7.5A + 0.75B

Step 4: Rearranging the equation, we get:

10B - 0.75B = 7.5A - A

9.25B = 6.5A

Step 5: We are also given that the difference of squares of the tens digit and units digit of the second number is 20. This can be represented as:

A^2 - B^2 = 20

Step 6: Simplifying the equation, we get:

(A + B)(A - B) = 20

Step 7: Now, we need to find the values of A and B that satisfy both equations simultaneously.

By trial and error, we can find that A = 5 and B = 3 satisfy both equations.

Step 8: Therefore, the first two-digit number is 53.

This problem has been solved

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