For a reaction, H = 198 kJ. For which value of TS is the reaction spontaneous?A.0 kJB.396 kJC.-198 kJD.198 kJ
Question
For a reaction, H = 198 kJ. For which value of TS is the reaction spontaneous?A.0 kJB.396 kJC.-198 kJD.198 kJ
Solution
The spontaneity of a reaction is determined by the Gibbs Free Energy equation, which is ΔG = ΔH - TΔS. For a reaction to be spontaneous, ΔG must be less than 0.
Given that ΔH = 198 kJ, we can rearrange the equation to solve for TΔS:
TΔS = ΔH - ΔG
Since we want ΔG to be less than 0 for spontaneity, we can set ΔG to be 0 for the threshold of spontaneity:
TΔS = ΔH - 0 TΔS = 198 kJ
Therefore, for the reaction to be spontaneous, TΔS must be greater than 198 kJ. So, the correct answer is B. 396 kJ.
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