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Suppose limx→t−f(x)=limx→t−g(x)lim𝑥→𝑡−⁡𝑓(𝑥)=lim𝑥→𝑡−⁡𝑔(𝑥) and limx→t+f(x)=limx→t+g(x)lim𝑥→𝑡+⁡𝑓(𝑥)=lim𝑥→𝑡+⁡𝑔(𝑥). Then, is limx→tf(x)=limx→tg(x)lim𝑥→𝑡⁡𝑓(𝑥)=lim𝑥→𝑡⁡𝑔(𝑥) true?

Question

Suppose limx→t−f(x)=limx→t−g(x)lim𝑥→𝑡−⁡𝑓(𝑥)=lim𝑥→𝑡−⁡𝑔(𝑥) and limx→t+f(x)=limx→t+g(x)lim𝑥→𝑡+⁡𝑓(𝑥)=lim𝑥→𝑡+⁡𝑔(𝑥). Then, is limx→tf(x)=limx→tg(x)lim𝑥→𝑡⁡𝑓(𝑥)=lim𝑥→𝑡⁡𝑔(𝑥) true?

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Solution

Yes, the statement is true. If the left-hand limit and the right-hand limit of the functions f(x) and g(x) are equal as x approaches t, then the overall limit of f(x) and g(x) as x approaches t will also be equal. This is because the overall limit of a function at a point is defined only when the left-hand limit and the right-hand limit exist and are equal. Since both these conditions are satisfied for both f(x) and g(x), we can say that limx→tf(x)=limx→tg(x).

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