why? #AlwaysAskWhyBecause this will be the third opened file descriptor for my processI don’t care I never ask why, just let me access the tasks!Because this will be the first opened file descriptor and in CS we start counting starting from 0Because this will be the second opened file descriptor for my processBecause most of the time, I will already have stdin (value 0), stdout (value 1) and stderr (value 2) opened when my program starts executing.Because this will be the first opened file descriptor and we start counting starting from 1
Question
why? #AlwaysAskWhyBecause this will be the third opened file descriptor for my processI don’t care I never ask why, just let me access the tasks!Because this will be the first opened file descriptor and in CS we start counting starting from 0Because this will be the second opened file descriptor for my processBecause most of the time, I will already have stdin (value 0), stdout (value 1) and stderr (value 2) opened when my program starts executing.Because this will be the first opened file descriptor and we start counting starting from 1
Solution
The correct answer is "Because most of the time, I will already have stdin (value 0), stdout (value 1) and stderr (value 2) opened when my program starts executing."
In Unix-like operating systems, when a process starts executing, it will typically have three file descriptors already opened: stdin (standard input), stdout (standard output), and stderr (standard error). These have the values 0, 1, and 2, respectively. Therefore, the next file descriptor that is opened will typically have the value 3.
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