A photon, an electron, and a helium atom all have the same momentum. The particle(s) with the largest de Broglie wavelength is (are)Select one:a.the photon.b.the electron.c.the helium atom.d.the electron and the helium atom.e.all three have the same wavelength.
Question
A photon, an electron, and a helium atom all have the same momentum. The particle(s) with the largest de Broglie wavelength is (are)Select one:a.the photon.b.the electron.c.the helium atom.d.the electron and the helium atom.e.all three have the same wavelength.
Solution
The de Broglie wavelength is given by the equation λ = h/p, where h is Planck's constant and p is the momentum of the particle. Since all three particles have the same momentum, the particle with the smallest mass will have the largest de Broglie wavelength.
The mass of a photon is zero, the mass of an electron is very small, and the mass of a helium atom is much larger than that of an electron. Therefore, the photon will have the largest de Broglie wavelength, followed by the electron, and then the helium atom.
So, the correct answer is a. the photon.
Similar Questions
The de-Broglie wavelength of an electron is the same as that of a photon. If velocity of electron is 25% of the velocity of light, then the ratio of K.E. of electron and K.E. of photon will be:
The de-Broglie wavelength of an electron moving with a velocity c3(c=3×108 m/s) is equal to the wavelength of photon. The ratio of the kinetic energies of electron and photon is
The momentum of three microparticles A, B, and C are the same and their mass ratio is 1: 3: 5. The ratio of their de-Broglie wavelength is
De Broglie wavelength was found to be equal toa.Compton wavelengthb.Photon wavelengthc.Bragg wavelength
The de Broglie wavelength of an electron in the 4th Bohr orbit is :
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.