Solve for xx:minus, 10, x, plus, 3, left parenthesis, 3, x, plus, 4, right parenthesis, plus, 1, equals, minus, 3, left parenthesis, 7, x, plus, 3, right parenthesis−10x+3(3x+4)+1=−3(7x+3)
Question
Solve for xx:minus, 10, x, plus, 3, left parenthesis, 3, x, plus, 4, right parenthesis, plus, 1, equals, minus, 3, left parenthesis, 7, x, plus, 3, right parenthesis−10x+3(3x+4)+1=−3(7x+3)
Solution
First, let's simplify the equation by distributing the numbers outside the parentheses:
-10x + 3*(3x) + 34 + 1 = -3(7x) - 3*3
This simplifies to:
-10x + 9x + 12 + 1 = -21x - 9
Combine like terms:
-x + 13 = -21x - 9
Next, let's isolate x by adding 21x to both sides:
20x + 13 = -9
Then, subtract 13 from both sides:
20x = -22
Finally, divide both sides by 20 to solve for x:
x = -22/20
Simplify the fraction:
x = -11/10
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