4. Determine whether x3 is O(g(x)) for each of these functions g(x).a) g(x) = x2 b) g(x) = x3 c) g(x) = x2 + x3d) g(x) = x2 + x4 e) g(x) = 3x f ) g(x) = x3/2
Question
- Determine whether x3 is O(g(x)) for each of these functions g(x).a) g(x) = x2 b) g(x) = x3 c) g(x) = x2 + x3d) g(x) = x2 + x4 e) g(x) = 3x f ) g(x) = x3/2
Solution 1
a) No, x^3 is not O(x^2) because x^3 grows faster than x^2 for large x.
b) Yes, x^3 is O(x^3) because they grow at the same rate.
c) Yes, x^3 is O(x^2 + x^3) because x^3 is the dominant term and determines the growth rate.
d) No, x^3 is not O(x^2 + x^4) because x^4 grows faster than x^3 for large x.
e) No, x^3 is not O(3x) because x^3 grows faster than 3x for large x.
f) No, x^3 is not O(x^3/2) because x^3 grows faster than x^3/2 for large x.
Solution 2
a) No, x^3 is not O(x^2) because x^3 grows faster than x^2 for large x.
b) Yes, x^3 is O(x^3) because they are the same function and grow at the same rate.
c) Yes, x^3 is O(x^2 + x^3) because x^3 is the dominant term and determines the growth rate of the function.
d) No, x^3 is not O(x^2 + x^4) because x^4 grows faster than x^3 for large x.
e) No, x^3 is not O(3x) because x^3 grows faster than 3x for large x.
f) No, x^3 is not O(x^3/2) because x^3 grows faster than x^3/2 for large x.
Similar Questions
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