The line of symmetry for a parabolic curve given by the equation y = ax^2 + bx + c is x = -b/2a.

In the equation y = 12x^2 - 5, a = 12 and b = 0 (since there is no x term).

So, the line of symmetry is x = -0/(2*12) = 0.

Therefore, the line of symmetry of the curve y = 12x^2 - 5 is x = 0.

Question

The line of symmetry for a parabolic curve given by the equation y = ax^2 + bx + c is x = -b/2a.

In the equation y = 12x^2 - 5, a = 12 and b = 0 (since there is no x term).

So, the line of symmetry is x = -0/(2*12) = 0.

Therefore, the line of symmetry of the curve y = 12x^2 - 5 is x = 0.

Knowee AI · Accepted Answer

The line of symmetry for a parabolic curve given by the equation y = ax^2 + bx + c is x = -b/2a.

In the equation y = 12x^2 - 5, a = 12 and b = 0 (since there is no x term).

So, the line of symmetry is x = -0/(2*12) = 0.

Therefore, the line of symmetry of the curve y = 12x^2 - 5 is x = 0.

Find the line of symmetry of the curve y=12x2−5.