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Precise measurements give the following masses:nuclide mass23892U 238.05079u23992U 239.05429uparticle mass10n 1.0086649u0−1e ×5.485810−4u01e ×5.485810−4uNow consider the following nuclear reaction:→+23892U  10n  23992UIs energy released or absorbed by this reaction? releasedabsorbedneither releasednor absorbedI need moreinformation to decide.If you said energy was released or absorbed, calculate how much energy is released or absorbed.kJ/molGive your answer in both kJ/mol and MeV. Be sure each of your answer entries has the correct number of significant digits.Note: take particular care to keep enough digits in any intermediate calculation, and use enough digits in any scientific constants you need, since the data with which you are working are very precise. MeV

Question

Precise measurements give the following masses:nuclide mass23892U 238.05079u23992U 239.05429uparticle mass10n 1.0086649u0−1e ×5.485810−4u01e ×5.485810−4uNow consider the following nuclear reaction:→+23892U  10n  23992UIs energy released or absorbed by this reaction? releasedabsorbedneither releasednor absorbedI need moreinformation to decide.If you said energy was released or absorbed, calculate how much energy is released or absorbed.kJ/molGive your answer in both kJ/mol and MeV. Be sure each of your answer entries has the correct number of significant digits.Note: take particular care to keep enough digits in any intermediate calculation, and use enough digits in any scientific constants you need, since the data with which you are working are very precise. MeV

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Solution

To determine whether energy is released or absorbed in the reaction, we need to calculate the mass difference before and after the reaction. This is based on the principle of mass-energy equivalence, which states that mass can be converted into energy and vice versa.

The mass before the reaction is the sum of the masses of 23892U and 10n, which is 238.05079u + 1.0086649u = 239.0594549u.

The mass after the reaction is the mass of 23992U, which is 239.05429u.

The mass difference is 239.0594549u - 239.05429u = 0.0051649u.

Since the mass before the reaction is greater than the mass after the reaction, energy is released during the reaction.

To calculate the amount of energy released, we can use the equation E=mc^2, where m is the mass difference and c is the speed of light. However, since we are dealing with atomic units, we can use the conversion factor that 1u = 931.5 MeV/c^2.

So, the energy released is 0.0051649u * 931.5 MeV/c^2 = 4.81 MeV.

To convert this to kJ/mol, we can use the conversion factors that 1 MeV = 1.60218 x 10^-13 kJ and 1 mol = 6.022 x 10^23 particles.

So, the energy released is 4.81 MeV * 1.60218 x 10^-13 kJ/MeV * 6.022 x 10^23 mol = 4.63 x 10^10 kJ/mol.

Therefore, the energy released by the reaction is 4.81 MeV or 4.63 x 10^10 kJ/mol.

This problem has been solved

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