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An astronomical telescope has objective and eye-piece lenses of focal length 3.5m and 5cm respectively. Determine the magnifying power of the telescope when in normal adjustmentA 70B 17.5C 7.0D 0.7

Question

An astronomical telescope has objective and eye-piece lenses of focal length 3.5m and 5cm respectively. Determine the magnifying power of the telescope when in normal adjustmentA 70B 17.5C 7.0D 0.7

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Solution

The magnifying power of a telescope in normal adjustment is given by the ratio of the focal length of the objective lens to the focal length of the eyepiece lens.

Given: Focal length of objective lens (Fo) = 3.5m = 350cm (since 1m = 100cm) Focal length of eyepiece lens (Fe) = 5cm

The magnifying power (M) is given by the formula:

M = Fo/Fe

Substituting the given values into the formula, we get:

M = 350cm / 5cm = 70

So, the magnifying power of the telescope when in normal adjustment is 70. Therefore, the correct answer is A. 70.

This problem has been solved

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