Step 1: First, let's find out the total number of marbles in the bag. We have 3 red, 4 green, and 3 blue marbles. So, the total number of marbles is 3 + 4 + 3 = 10 marbles.

Step 2: We are asked to find the probability that neither of the selected marbles is blue. This means we are only considering the red and green marbles. There are 3 red and 4 green marbles, so there are 3 + 4 = 7 marbles that are not blue.

Step 3: The probability of picking one marble that is not blue is the number of non-blue marbles divided by the total number of marbles. So, the probability is 7/10.

Step 4: However, we are picking two marbles without replacement. This means after we pick the first marble, we don't put it back in the bag. So, for the second pick, there is one less marble in the bag and one less non-blue marble.

Step 5: The probability of picking a second marble that is not blue is (7 - 1) / (10 - 1) = 6/9.

Step 6: The probability of both events happening (picking two marbles that are not blue) is the product of the probabilities of each event. So, the probability is (7/10) * (6/9) = 42/90 = 0.467.

So, the probability that neither of the selected marbles is blue is approximately 0.467, or 46.7%.

Question

Step 1: First, let's find out the total number of marbles in the bag. We have 3 red, 4 green, and 3 blue marbles. So, the total number of marbles is 3 + 4 + 3 = 10 marbles.

Step 2: We are asked to find the probability that neither of the selected marbles is blue. This means we are only considering the red and green marbles. There are 3 red and 4 green marbles, so there are 3 + 4 = 7 marbles that are not blue.

Step 3: The probability of picking one marble that is not blue is the number of non-blue marbles divided by the total number of marbles. So, the probability is 7/10.

Step 4: However, we are picking two marbles without replacement. This means after we pick the first marble, we don't put it back in the bag. So, for the second pick, there is one less marble in the bag and one less non-blue marble.

Step 5: The probability of picking a second marble that is not blue is (7 - 1) / (10 - 1) = 6/9.

Step 6: The probability of both events happening (picking two marbles that are not blue) is the product of the probabilities of each event. So, the probability is (7/10) * (6/9) = 42/90 = 0.467.

So, the probability that neither of the selected marbles is blue is approximately 0.467, or 46.7%.

Knowee AI · Accepted Answer

Step 1: First, let's find out the total number of marbles in the bag. We have 3 red, 4 green, and 3 blue marbles. So, the total number of marbles is 3 + 4 + 3 = 10 marbles.

Step 2: We are asked to find the probability that neither of the selected marbles is blue. This means we are only considering the red and green marbles. There are 3 red and 4 green marbles, so there are 3 + 4 = 7 marbles that are not blue.

Step 3: The probability of picking one marble that is not blue is the number of non-blue marbles divided by the total number of marbles. So, the probability is 7/10.

Step 4: However, we are picking two marbles without replacement. This means after we pick the first marble, we don't put it back in the bag. So, for the second pick, there is one less marble in the bag and one less non-blue marble.

Step 5: The probability of picking a second marble that is not blue is (7 - 1) / (10 - 1) = 6/9.

Step 6: The probability of both events happening (picking two marbles that are not blue) is the product of the probabilities of each event. So, the probability is (7/10) * (6/9) = 42/90 = 0.467.

So, the probability that neither of the selected marbles is blue is approximately 0.467, or 46.7%.

Inside a bag, there are 3 red, 4 green and 3 blue marbles. If you were to pick out two marbles without looking, what is the probability that neither of the selected marbles is blue?

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