To solve this problem, we need to use the Pythagorean theorem and the properties of parallel chords in a circle.

Step 1: Find the distance from the center of the circle to each chord.

The distance from the center of the circle to a chord can be found using the Pythagorean theorem. The radius of the circle is the hypotenuse of a right triangle, the half-length of the chord is one leg, and the distance from the center to the chord is the other leg.

For chord AB, half the length is 12/2 = 6 cm. So, the distance from the center to chord AB is sqrt(10^2 - 6^2) = sqrt(64) = 8 cm.

For chord CD, half the length is 16/2 = 8 cm. So, the distance from the center to chord CD is sqrt(10^2 - 8^2) = sqrt(36) = 6 cm.

Step 2: Find the distance between the two chords.

The distance between the two chords is the difference in the distances from the center to each chord. So, the distance between chords AB and CD is 8 cm - 6 cm = 2 cm.

Question

To solve this problem, we need to use the Pythagorean theorem and the properties of parallel chords in a circle.

Step 1: Find the distance from the center of the circle to each chord.

The distance from the center of the circle to a chord can be found using the Pythagorean theorem. The radius of the circle is the hypotenuse of a right triangle, the half-length of the chord is one leg, and the distance from the center to the chord is the other leg.

For chord AB, half the length is 12/2 = 6 cm. So, the distance from the center to chord AB is sqrt(10^2 - 6^2) = sqrt(64) = 8 cm.

For chord CD, half the length is 16/2 = 8 cm. So, the distance from the center to chord CD is sqrt(10^2 - 8^2) = sqrt(36) = 6 cm.

Step 2: Find the distance between the two chords.

The distance between the two chords is the difference in the distances from the center to each chord. So, the distance between chords AB and CD is 8 cm - 6 cm = 2 cm.

Knowee AI · Accepted Answer

To solve this problem, we need to use the Pythagorean theorem and the properties of parallel chords in a circle.

Step 1: Find the distance from the center of the circle to each chord.

The distance from the center of the circle to a chord can be found using the Pythagorean theorem. The radius of the circle is the hypotenuse of a right triangle, the half-length of the chord is one leg, and the distance from the center to the chord is the other leg.

For chord AB, half the length is 12/2 = 6 cm. So, the distance from the center to chord AB is sqrt(10^2 - 6^2) = sqrt(64) = 8 cm.

For chord CD, half the length is 16/2 = 8 cm. So, the distance from the center to chord CD is sqrt(10^2 - 8^2) = sqrt(36) = 6 cm.

Step 2: Find the distance between the two chords.

The distance between the two chords is the difference in the distances from the center to each chord. So, the distance between chords AB and CD is 8 cm - 6 cm = 2 cm.

Parallel chords AB and CD are on the same side of the centre of a circle of radius 10 having their lengths 12 cm and 16 cm. The distance between the two chords is

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