What velocity is an object moving at after 4.0s if it is initially moving at 10.5m/s and is moving at 13.5m/s after 2.0s?

To solve this problem, we first need to find the acceleration of the object. Acceleration is the rate of change of velocity per unit of time.

Step 1: Find the change in velocity The change in velocity (Δv) is the final velocity (v_f) minus the initial velocity (v_i). In this case, v_f is 13.5 m/s and v_i is 10.5 m/s. So, Δv = 13.5 m/s - 10.5 m/s = 3.0 m/s.

Step 2: Find the time over which the change in velocity occurred The time (Δt) over which the change in velocity occurred is 2.0 s.

Step 3: Calculate the acceleration Acceleration (a) is the change in velocity divided by the time. So, a = Δv / Δt = 3.0 m/s / 2.0 s = 1.5 m/s².

Step 4: Use the acceleration to find the velocity after 4.0 s The final velocity (v_f) after a certain time (t) can be found using the equation v_f = v_i + a*t. In this case, v_i is 10.5 m/s, a is 1.5 m/s², and t is 4.0 s. So, v_f = 10.5 m/s + 1.5 m/s² * 4.0 s = 16.5 m/s.

So, the object is moving at 16.5 m/s after 4.0 s.