A body rises vertically upward to a height of 100 m, in 5 seconds, then comes back to the same position after another 5 s. Find the average speed of the body in m/s.
Question
A body rises vertically upward to a height of 100 m, in 5 seconds, then comes back to the same position after another 5 s. Find the average speed of the body in m/s.
Solution
To find the average speed of the body, we need to calculate the total distance traveled and divide it by the total time taken.
First, let's calculate the total distance traveled. The body rises vertically upward to a height of 100 m and then comes back to the same position. So, the total distance traveled is twice the height, which is 2 * 100 m = 200 m.
Next, let's calculate the total time taken. The body takes 5 seconds to rise and another 5 seconds to come back down. So, the total time taken is 5 s + 5 s = 10 s.
Now, we can calculate the average speed by dividing the total distance traveled by the total time taken. Therefore, the average speed of the body is 200 m / 10 s = 20 m/s.
Similar Questions
A body rises vertically upward to a height of 100 m, in 5 seconds, then comes back to the same position after another 5 s. Find the distance travelled in m.
A body rises vertically upward to a height of 100 m, in 5 seconds, then comes back to the same position after another 5 s. Find the displacement of the body.
A body is thrown vertically upward with 45 m/s. Distance travelled by the body in 5th second is (g = 10 m/s2)
A body moving with uniform acceleration travels 84mts in the first 6 second and180m in the next 5 sec. Find the initial velocity & acceleration of bodyA) 23 / s , 4 /m m s B) 29 / s, 2 / sm m C) 22 / s , 3 /m m s D) 22 / s , 4 /m m s
A car accelerates from 5 m/s to 25 m/s in 100 m.What is the car's average acceleration?
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.