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If the diagonals AC and BD of a quadrilateral ABCD, intersect at D and separate   the quadrilateral into four triangles of equal area, then the quadrilateral ABCD is

Question

If the diagonals AC and BD of a quadrilateral ABCD, intersect at D and separate   the quadrilateral into four triangles of equal area, then the quadrilateral ABCD is

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Solution

The quadrilateral ABCD is a square.

Here's the step-by-step explanation:

  1. The diagonals of a quadrilateral divide it into four triangles. If these triangles have equal areas, then each pair of opposite triangles are congruent (have the same size and shape).

  2. In a quadrilateral, if the diagonals bisect each other (intersect at their midpoints), the quadrilateral is a parallelogram.

  3. In a parallelogram, if the diagonals are of equal length, then it is a rectangle.

  4. In a rectangle, if the sides are of equal length, then it is a square.

  5. Therefore, if the diagonals of a quadrilateral bisect each other and divide the quadrilateral into four triangles of equal area, the quadrilateral is a square.

This problem has been solved

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