Knowee
Questions
Features
Study Tools

Select all true statements1 pointThere are languages A, B such that A is regular, B is undecidable, and A is a superset of B.There are languages A, B such that A is regular, B is undecidable, and A is a subset of B.There are languages A, B such that A is context-free, B is undecidable, and A is a subset of B.There are languages A, B such that A is context-free, B is undecidable, and A is a superset of B.

Question

Select all true statements1 pointThere are languages A, B such that A is regular, B is undecidable, and A is a superset of B.There are languages A, B such that A is regular, B is undecidable, and A is a subset of B.There are languages A, B such that A is context-free, B is undecidable, and A is a subset of B.There are languages A, B such that A is context-free, B is undecidable, and A is a superset of B.

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

The correct statement is: "There are languages A, B such that A is regular, B is undecidable, and A is a subset of B."

Here's why:

  1. "There are languages A, B such that A is regular, B is undecidable, and A is a superset of B." - This is false. A regular language (A) cannot be a superset of an undecidable language (B) because regular languages are a subset of decidable languages.

  2. "There are languages A, B such that A is regular, B is undecidable, and A is a subset of B." - This is true. A regular language (A) can be a subset of an undecidable language (B). For example, the language of all strings over {0,1} is undecidable, but it includes the regular language of all strings of 0s.

  3. "There are languages A, B such that A is context-free, B is undecidable, and A is a subset of B." - This is true. A context-free language (A) can be a subset of an undecidable language (B). For example, the language of all strings over {0,1} is undecidable, but it includes the context-free language of all palindromes over {0,1}.

  4. "There are languages A, B such that A is context-free, B is undecidable, and A is a superset of B." - This is false. A context-free language (A) cannot be a superset of an undecidable language (B) because context-free languages are a subset of decidable languages.

This problem has been solved

Similar Questions

Select all true statements1 pointThere is a TM that loops on all inputsLet A be any decidable language. There is a TM that loops on exactly the strings not in A.Let A be any decidable language. There is a TM that loops on exactly the strings in A.There is an undecidable language A such that there is a TM that halts on exactly the strings in A.There is an undecidable language A such that the complement of A is decidable.There is a decidable language A such that the complement of A is undecidable.

Let A be some decidable language and let B be some undecidable language. Select all statements that are definitely false no matter what A and B are.1 pointA ≤ AA ≤ BB ≤ AB ≤ BB ≤ HALTSHALTS ≤ B

Select all true statements1 pointAll finite languages are regular.All infinite languages are regularAll infinite languages are context-free.All finite languages are context-free.

A is some decidable language. Select all statements that are true irrespective of what A is.1 pointHALTS ≤ HALTS'HALTS' ≤ HALTSA ≤ HALTS'HALTS' ≤ A

Select all true statements, for all A, B1 pointIf A and B are decidable, then A union B is decidable.If A and B are decidable, then A intersection B is decidable.If A union B is decidable, then A is decidable and B is decidable.If A intersection B is decidable, then A is decidable and B is decidable.If A union B is decidable, then A is decidable or B is decidable.If A intersection B is decidable, then A is decidable or B is decidable.

1/2

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.