If the water pressure gauge shows the pressure at ground floor to be 270 k Pa, how high would water (Ans. 27.6 m

The question seems to be asking for the height of a column of water that would produce a pressure of 270 kPa.

The pressure at a certain depth (or height) in a fluid is given by the equation P = ρgh, where:

• P is the pressure,
• ρ is the fluid density,
• g is the acceleration due to gravity, and
• h is the height of the fluid column above the point in question.

We can rearrange this equation to solve for h: h = P / (ρg).

The density of water is approximately 1000 kg/m³, and the acceleration due to gravity is approximately 9.81 m/s². So we can substitute these values into the equation to find the height:

h = 270,000 Pa / (1000 kg/m³ * 9.81 m/s²) = 27.6 m.

So a water pressure of 270 kPa corresponds to a water column height of approximately 27.6 meters.