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The Cramér-Rao Lower Bound (CRLB) provides a lower bound on the variance of unbiased estimators of a parameter. To find the CRLB for the variance of an unbiased estimator of the parameter \(\theta\), we need to calculate the Fisher information \(I(\theta)\) for a single observation from the given probability density function (pdf) \(f(x;\theta)\). The Fisher information is given by: \[ I(\theta) = -E\left[\frac{\partial^2}{\partial \theta^2} \ln f(X;\theta)\right] \] Given the pdf: \[ f(x;\theta) = \begin{cases} 3a\theta^2 e^{-\theta x^3}, & 0 < x < \infty \\ 0, & \text{otherwise} \end{cases} \] First, we need to compute the natural logarithm of the pdf: \[ \ln f(x;\theta) = \ln(3a) + 2\ln(\theta) - \theta x^3 \] Now, we take the first derivative with respect to \(\theta\): \[ \frac{\partial}{\partial \theta} \ln f(x;\theta) = \frac{2}{\theta} - x^3 \] Next, we take the second derivative with respect to \(\theta\): \[ \frac{\partial^2}{\partial \theta^2} \ln f(x;\theta) = -\frac{2}{\theta^2} \] Now, we calculate the expected value of the second derivative. Since the second derivative does not depend on \(x\), the expected value is simply the negative of the second derivative itself: \[ E\left[-\frac{\partial^2}{\partial \theta^2} \ln f(X;\theta)\right] = E\left[\frac{2}{\theta^2}\right] = \frac{2}{\theta^2} \] Therefore, the Fisher information for a single observation is: \[ I(\theta) = \frac{2}{\theta^2} \] For a sample of size \(n\), the Fisher information is \(n\) times the information for a single observation, since the observations are independent: \[ I_n(\theta) = nI(\theta) = \frac{2n}{\theta^2} \] The Cramér-Rao Lower Bound for the variance of any unbiased estimator \(\hat{\theta}\) of \(\theta\) is then given by the reciprocal of the Fisher information for the sample: \[ \text{Var}(\hat{\theta}) \geq \frac{1}{I_n(\theta)} = \frac{\theta^2}{2n} \] This is the Cramér-Rao Lower Bound for the variance of unbiased estimators of the parameter \(\theta\).

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The Cramér-Rao Lower Bound (CRLB) provides a lower bound on the variance of unbiased estimators of a parameter. To find the CRLB for the variance of an unbiased estimator of the parameter θ\theta, we need to calculate the Fisher information I(θ)I(\theta) for a single observation from the given probability density function (pdf) f(x;θ)f(x;\theta). The Fisher information is given by: I(θ)=E[2θ2lnf(X;θ)] I(\theta) = -E\left[\frac{\partial^2}{\partial \theta^2} \ln f(X;\theta)\right] Given the pdf: f(x;θ)={3aθ2eθx3,0<x<0,otherwise f(x;\theta) = \begin{cases} 3a\theta^2 e^{-\theta x^3}, & 0 < x < \infty \\ 0, & \text{otherwise} \end{cases} First, we need to compute the natural logarithm of the pdf: lnf(x;θ)=ln(3a)+2ln(θ)θx3 \ln f(x;\theta) = \ln(3a) + 2\ln(\theta) - \theta x^3 Now, we take the first derivative with respect to θ\theta: θlnf(x;θ)=2θx3 \frac{\partial}{\partial \theta} \ln f(x;\theta) = \frac{2}{\theta} - x^3 Next, we take the second derivative with respect to θ\theta: 2θ2lnf(x;θ)=2θ2 \frac{\partial^2}{\partial \theta^2} \ln f(x;\theta) = -\frac{2}{\theta^2} Now, we calculate the expected value of the second derivative. Since the second derivative does not depend on xx, the expected value is simply the negative of the second derivative itself: E[2θ2lnf(X;θ)]=E[2θ2]=2θ2 E\left[-\frac{\partial^2}{\partial \theta^2} \ln f(X;\theta)\right] = E\left[\frac{2}{\theta^2}\right] = \frac{2}{\theta^2} Therefore, the Fisher information for a single observation is: I(θ)=2θ2 I(\theta) = \frac{2}{\theta^2} For a sample of size nn, the Fisher information is nn times the information for a single observation, since the observations are independent: In(θ)=nI(θ)=2nθ2 I_n(\theta) = nI(\theta) = \frac{2n}{\theta^2} The Cramér-Rao Lower Bound for the variance of any unbiased estimator θ^\hat{\theta} of θ\theta is then given by the reciprocal of the Fisher information for the sample: Var(θ^)1In(θ)=θ22n \text{Var}(\hat{\theta}) \geq \frac{1}{I_n(\theta)} = \frac{\theta^2}{2n} This is the Cramér-Rao Lower Bound for the variance of unbiased estimators of the parameter θ\theta.

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