A 10 kg box is on a concrete floor. You first push it with 2 N and the box does not move. Then you increase your force to 8 N and still the box does not move. Finally you apply 10.5 N and the box starts sliding on the floor. How much is the force of friction in each one of these cases, respectively. Group of answer choicesless than 2N, less than 8N, less than 10.5Nmore than 2N, more than 8N, 10.5N2N, 8N, less than 10.5N2N, 8N, 10.5Nmore than 2N, more that 8N, less than 10.5N
Question
A 10 kg box is on a concrete floor. You first push it with 2 N and the box does not move. Then you increase your force to 8 N and still the box does not move. Finally you apply 10.5 N and the box starts sliding on the floor. How much is the force of friction in each one of these cases, respectively. Group of answer choicesless than 2N, less than 8N, less than 10.5Nmore than 2N, more than 8N, 10.5N2N, 8N, less than 10.5N2N, 8N, 10.5Nmore than 2N, more that 8N, less than 10.5N
Solution
The force of friction in each case would be 2N, 8N, less than 10.5N.
Here's why:
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When you push the box with 2N and it doesn't move, the force of friction is equal to the applied force, which is 2N.
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When you increase your force to 8N and the box still doesn't move, the force of friction again equals the applied force, which is now 8N.
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When you apply 10.5N and the box starts to move, the force of friction is less than the applied force. This is because the box wouldn't move unless the applied force was greater than the force of friction. So in this case, the force of friction is less than 10.5N.
So, the correct answer is "2N, 8N, less than 10.5N".
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