An object is placed 70.3 cm to the left of a diverging lens. A virtual image is formed 12.9 cm to the left of the lens. Determine the focal length of the lens. Enter a – answer if appropriate.Focal Lengthcm
Question
An object is placed 70.3 cm to the left of a diverging lens. A virtual image is formed 12.9 cm to the left of the lens. Determine the focal length of the lens. Enter a – answer if appropriate.Focal Lengthcm
Solution
To find the focal length of the lens, we can use the lens formula:
1/f = 1/v - 1/u
where: f is the focal length, v is the image distance, and u is the object distance.
Given in the problem, u = -70.3 cm (the negative sign indicates that the object is on the same side of the lens as the light being used) and v = -12.9 cm (the negative sign indicates that the image is virtual and on the same side of the lens as the object).
Substituting these values into the lens formula gives:
1/f = 1/(-12.9 cm) - 1/(-70.3 cm)
Solving this equation for f gives:
f = 1 / [(1/-12.9) - (1/-70.3)]
After calculating the above expression, we get:
f = -17.8 cm
The negative sign indicates that the lens is a diverging lens.
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