Findtheequationoftheaxisofsymmetryfortheparabolay = x2 − 4x.
Question
Findtheequationoftheaxisofsymmetryfortheparabolay = x2 − 4x.
Solution
The axis of symmetry for a parabola given by the equation y = ax^2 + bx + c is given by the formula x = -b/2a.
In the equation y = x^2 - 4x, a = 1 and b = -4.
Substituting these values into the formula gives:
x = -(-4)/2(1) x = 4/2 x = 2
So, the equation of the axis of symmetry for the parabola y = x^2 - 4x is x = 2.
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